Wristwatch Parts And Functions
Help with the issue of business income?
Please help me solve these. you do not give me the answers, it'll just get me started or point me to a city were they have problems like these. million. 1 Thank you. a) A monthly income realized by selling wristwatches x is represented in R (x) = 75x – 0.2x ^ 2 C. The monthly cost of the sale of wristwatches is C x (x) = 32x + 1750. a.) how many wristwatches the company must sell to maximize revenues? What is the maximum revenue -?) B. profit is given as P (x) = R (x) C (x). what is the function profit? c.) how many wristwatches have to sell the company to maximize profits? what is the maximum profit? d.) provide a reasonable explanation as to why for which the answers in parts a.) and c) why differ.explain a quadratic function is a reasonable model for revenue.
a) Maximize as a function R (x) can be made with the calculation: take the derivative (dR / dx), which together = zero, and solve for x. Except not familiar with calculus, try the link. This fact gives you a "turning point" (TP) that can be a maximum or a minimum or "inflection" point – but I doubt you will get one of those in business) math. (To check that TP is a maximum, to differentiate a second time (d2R/dx2) and insert the value of x you find dR / dx = 0, if the answer is-ve you up, if you have a + ve minimum, and if it is 0 you have an inflection point! To find a maximum revenue, put the value of x you found in the equation R (x). b) Combining the two functions by subtracting term by term. The profit function is the expression of P (x). c) Similar to one). Another "maximize" problem, this time using P (x). D) Explain why or revenue maximization is not the same as profit maximization. It's a deal – I guess you can answer this. (Revenue excludes costs?) E) Why is a quadratic function a reasonable model for R? Income = sales volume (X) times the price. The price depends on the volume sold: the more you are ready to sell per week and your average price will be to get all sold. Example, if there is a fixed number of buyers with a variety of income, then you might be able to sell the first 10 per month for £ 30 each by placing on the market High Street jeweler. If you want sell an extra 10 per month you may have to reduce the price of £ 15 and sell it in Asda / Wal-Mart. And to move another 10 per month you may have to sell from a stall at £ 5 each! Assuming the average price you can sell for decreases linearly (each additional sales striking the same amount on the price) with the volume of sales (x), your price function could look like – Bx. (This is not very realistic, but it could be roughly true for the range of x that you plan to sell such -. 100-150 per month) so x times income = (A Bx) = Ax – Bx ^ 2. A quadratic function.
Jaeger LeCoultre Reverso Gyrotourbillon 2
